(1/4)^(-3x+4)=8^(x-1)

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Solution for (1/4)^(-3x+4)=8^(x-1) equation: 



(1/4)^(-3x+4)=8^(x-1)

We move all terms to the left:

(1/4)^(-3x+4)-(8^(x-1))=0



Domain of the equation: 4)^(-3x+4)!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)^(-3x+4)-(8^(x-1))=0

We multiply all the terms by the denominator


(+1-((8^(x-1)))*4)^(-3x+4)=0



We calculate terms in parentheses: +(+1-((8^(x-1)))*4)^(-3x+4), so:

+1-((8^(x-1)))*4)^(-3x+4

determiningTheFunctionDomain
-((8^(x-1)))*4)^(-3x+1+4

We add all the numbers together, and all the variables

-3x-((8^(x-1)))*4)^(+5

Back to the equation:

+(-3x-((8^(x-1)))*4)^(+5)



We add all the numbers together, and all the variables

(-3x-((8^(x-1)))*4)^5=0

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